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10344013211 = 71477716173
BaseRepresentation
bin10011010001000110…
…10001110110011011
3222200220002022112102
421220203101312123
5132141031410321
64430232034015
7514222442630
oct115043216633
928626068472
1010344013211
114428a20254
12200823290b
13c8b05869c
14701b12187
154081b2c0b
hex2688d1d9b

10344013211 has 4 divisors (see below), whose sum is σ = 11821729392. Its totient is φ = 8866297032.

The previous prime is 10344013201. The next prime is 10344013213. The reversal of 10344013211 is 11231044301.

10344013211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10344013211 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10344013213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 738858080 + ... + 738858093.

It is an arithmetic number, because the mean of its divisors is an integer number (2955432348).

Almost surely, 210344013211 is an apocalyptic number.

10344013211 is a deficient number, since it is larger than the sum of its proper divisors (1477716181).

10344013211 is an equidigital number, since it uses as much as digits as its factorization.

10344013211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1477716180.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 10344013211 its reverse (11231044301), we get a palindrome (21575057512).

The spelling of 10344013211 in words is "ten billion, three hundred forty-four million, thirteen thousand, two hundred eleven".

Divisors: 1 7 1477716173 10344013211