Base | Representation |
---|---|
bin | 1001011010000110110101… |
… | …0000101100111010000011 |
3 | 1100121212222010002010101121 |
4 | 2112201231100230322003 |
5 | 2323434221232443210 |
6 | 34000004233413111 |
7 | 2115223540116316 |
oct | 226415520547203 |
9 | 40555863063347 |
10 | 10344114343555 |
11 | 3328a06970593 |
12 | 11b0912b6a197 |
13 | 5a05a45544a5 |
14 | 27a92d03897d |
15 | 12e11a3e86da |
hex | 9686d42ce83 |
10344114343555 has 4 divisors (see below), whose sum is σ = 12412937212272. Its totient is φ = 8275291474840.
The previous prime is 10344114343553. The next prime is 10344114343571. The reversal of 10344114343555 is 55534341144301.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 10344114343555 - 21 = 10344114343553 is a prime.
It is a super-3 number, since 3×103441143435553 (a number of 40 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10344114343553) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1034411434351 + ... + 1034411434360.
It is an arithmetic number, because the mean of its divisors is an integer number (3103234303068).
Almost surely, 210344114343555 is an apocalyptic number.
10344114343555 is a deficient number, since it is larger than the sum of its proper divisors (2068822868717).
10344114343555 is an equidigital number, since it uses as much as digits as its factorization.
10344114343555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2068822868716.
The product of its (nonzero) digits is 864000, while the sum is 43.
Adding to 10344114343555 its reverse (55534341144301), we get a palindrome (65878455487856).
The spelling of 10344114343555 in words is "ten trillion, three hundred forty-four billion, one hundred fourteen million, three hundred forty-three thousand, five hundred fifty-five".
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