Base | Representation |
---|---|
bin | 10011010001001010… |
… | …10101011010110011 |
3 | 222200221002200202211 |
4 | 21220211111122303 |
5 | 132141201131430 |
6 | 4430251352551 |
7 | 514230146032 |
oct | 115045253263 |
9 | 28627080684 |
10 | 10344552115 |
11 | 4429259127 |
12 | 2008452757 |
13 | c8b1b6a71 |
14 | 701c12719 |
15 | 40826c72a |
hex | 2689556b3 |
10344552115 has 4 divisors (see below), whose sum is σ = 12413462544. Its totient is φ = 8275641688.
The previous prime is 10344552083. The next prime is 10344552121. The reversal of 10344552115 is 51125544301.
10344552115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 10344552115 - 25 = 10344552083 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1034455207 + ... + 1034455216.
It is an arithmetic number, because the mean of its divisors is an integer number (3103365636).
Almost surely, 210344552115 is an apocalyptic number.
10344552115 is a deficient number, since it is larger than the sum of its proper divisors (2068910429).
10344552115 is an equidigital number, since it uses as much as digits as its factorization.
10344552115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2068910428.
The product of its (nonzero) digits is 12000, while the sum is 31.
The spelling of 10344552115 in words is "ten billion, three hundred forty-four million, five hundred fifty-two thousand, one hundred fifteen".
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