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103512000051 = 3237310846847
BaseRepresentation
bin110000001100111001…
…0111100011000110011
3100220011221002102121200
41200121302330120303
53143443033000201
6115315221222243
710323060324465
oct1403162743063
9326157072550
10103512000051
113a998909789
1218089b61983
1399b82bb095
14501d664135
152a5c717386
hex1819cbc633

103512000051 has 12 divisors (see below), whose sum is σ = 153558342912. Its totient is φ = 67142918736.

The previous prime is 103512000041. The next prime is 103512000079. The reversal of 103512000051 is 150000215301.

103512000051 is a `hidden beast` number, since 103 + 512 + 0 + 0 + 0 + 0 + 51 = 666.

It is not a de Polignac number, because 103512000051 - 213 = 103511991859 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 103511999988 and 103512000033.

It is not an unprimeable number, because it can be changed into a prime (103512000041) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 155423091 + ... + 155423756.

It is an arithmetic number, because the mean of its divisors is an integer number (12796528576).

Almost surely, 2103512000051 is an apocalyptic number.

103512000051 is a deficient number, since it is larger than the sum of its proper divisors (50046342861).

103512000051 is a wasteful number, since it uses less digits than its factorization.

103512000051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 310846890 (or 310846887 counting only the distinct ones).

The product of its (nonzero) digits is 150, while the sum is 18.

Adding to 103512000051 its reverse (150000215301), we get a palindrome (253512215352).

The spelling of 103512000051 in words is "one hundred three billion, five hundred twelve million, fifty-one", and thus it is an aban number.

Divisors: 1 3 9 37 111 333 310846847 932540541 2797621623 11501333339 34504000017 103512000051