103540130045041 has 16 divisors (see below), whose sum is σ = 108104005964160. Its totient is φ = 98981436153600.

The previous prime is 103540130044999. The next prime is 103540130045047. The reversal of 103540130045041 is 140540031045301.

It is a cyclic number.

It is not a de Polignac number, because 103540130045041 - 2⁴⁵ = 68355757956209 is a prime.

It is a super-3 number, since 3×103540130045041³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 103540130044994 and 103540130045012.

It is not an unprimeable number, because it can be changed into a prime (103540130045047) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1854566115 + ... + 1854621943.

It is an arithmetic number, because the mean of its divisors is an integer number (6756500372760).

Almost surely, 2^{103540130045041} is an apocalyptic number.

It is an amenable number.

103540130045041 is a deficient number, since it is larger than the sum of its proper divisors (4563875919119).

103540130045041 is a wasteful number, since it uses less digits than its factorization.

103540130045041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 100776.

The product of its (nonzero) digits is 14400, while the sum is 31.

The spelling of 103540130045041 in words is "one hundred three trillion, five hundred forty billion, one hundred thirty million, forty-five thousand, forty-one".