Base | Representation |
---|---|
bin | 1001011010101100111110… |
… | …1011110011100001110001 |
3 | 1100122212101211201022222220 |
4 | 2112223033223303201301 |
5 | 2324121210010102241 |
6 | 34004420354151253 |
7 | 2116035404001066 |
oct | 226531753634161 |
9 | 40585354638886 |
10 | 10354355550321 |
11 | 3332291852832 |
12 | 11b28b0882529 |
13 | 5a15471c5b53 |
14 | 27b221228c6d |
15 | 12e519550166 |
hex | 96acfaf3871 |
10354355550321 has 4 divisors (see below), whose sum is σ = 13805807400432. Its totient is φ = 6902903700212.
The previous prime is 10354355550317. The next prime is 10354355550347. The reversal of 10354355550321 is 12305555345301.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 10354355550321 - 22 = 10354355550317 is a prime.
It is a super-3 number, since 3×103543555503213 (a number of 40 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (10354355560321) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1725725925051 + ... + 1725725925056.
It is an arithmetic number, because the mean of its divisors is an integer number (3451451850108).
Almost surely, 210354355550321 is an apocalyptic number.
It is an amenable number.
10354355550321 is a deficient number, since it is larger than the sum of its proper divisors (3451451850111).
10354355550321 is an equidigital number, since it uses as much as digits as its factorization.
10354355550321 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3451451850110.
The product of its (nonzero) digits is 675000, while the sum is 42.
The spelling of 10354355550321 in words is "ten trillion, three hundred fifty-four billion, three hundred fifty-five million, five hundred fifty thousand, three hundred twenty-one".
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