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10354364113 = 70423147031
BaseRepresentation
bin10011010010010101…
…10000111011010001
3222201121120012022011
421221022300323101
5132201204122423
64431241542521
7514406433322
oct115112607321
928647505264
1010354364113
114433850015
12200b7a4a41
13c90240b92
14703248449
15409059b0d
hex2692b0ed1

10354364113 has 4 divisors (see below), whose sum is σ = 10354581568. Its totient is φ = 10354146660.

The previous prime is 10354364107. The next prime is 10354364117. The reversal of 10354364113 is 31146345301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31146345301 = 297231047887.

It is a cyclic number.

It is not a de Polignac number, because 10354364113 - 25 = 10354364081 is a prime.

It is a super-3 number, since 3×103543641133 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10354364117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3093 + ... + 143938.

It is an arithmetic number, because the mean of its divisors is an integer number (2588645392).

Almost surely, 210354364113 is an apocalyptic number.

It is an amenable number.

10354364113 is a deficient number, since it is larger than the sum of its proper divisors (217455).

10354364113 is an equidigital number, since it uses as much as digits as its factorization.

10354364113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 217454.

The product of its (nonzero) digits is 12960, while the sum is 31.

The spelling of 10354364113 in words is "ten billion, three hundred fifty-four million, three hundred sixty-four thousand, one hundred thirteen".

Divisors: 1 70423 147031 10354364113