1035450131 has 4 divisors (see below), whose sum is σ = 1035531552. Its totient is φ = 1035368712.

The previous prime is 1035450113. The next prime is 1035450137. The reversal of 1035450131 is 1310545301.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 1310545301 = 13 ⋅100811177.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1035450131 is a prime.

It is a super-3 number, since 3×1035450131³ (a number of 28 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1035450097 and 1035450106.

It is not an unprimeable number, because it can be changed into a prime (1035450137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17051 + ... + 48596.

It is an arithmetic number, because the mean of its divisors is an integer number (258882888).

Almost surely, 2^1035450131 is an apocalyptic number.

1035450131 is a deficient number, since it is larger than the sum of its proper divisors (81421).

1035450131 is an equidigital number, since it uses as much as digits as its factorization.

1035450131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 81420.

The product of its (nonzero) digits is 900, while the sum is 23.

The square root of 1035450131 is about 32178.4109458500. The cubic root of 1035450131 is about 1011.6797623787.

Adding to 1035450131 its reverse (1310545301), we get a palindrome (2345995432).

The spelling of 1035450131 in words is "one billion, thirty-five million, four hundred fifty thousand, one hundred thirty-one".