10354550120131 has 4 divisors (see below), whose sum is σ = 11833771565872. Its totient is φ = 8875328674392.

The previous prime is 10354550120023. The next prime is 10354550120191. The reversal of 10354550120131 is 13102105545301.

10354550120131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10354550120131 - 2¹⁵ = 10354550087363 is a prime.

It is a super-3 number, since 3×10354550120131³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10354550120093 and 10354550120102.

It is not an unprimeable number, because it can be changed into a prime (10354550120191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 739610722860 + ... + 739610722873.

It is an arithmetic number, because the mean of its divisors is an integer number (2958442891468).

Almost surely, 2^{10354550120131} is an apocalyptic number.

10354550120131 is a deficient number, since it is larger than the sum of its proper divisors (1479221445741).

10354550120131 is an equidigital number, since it uses as much as digits as its factorization.

10354550120131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1479221445740.

The product of its (nonzero) digits is 9000, while the sum is 31.

Adding to 10354550120131 its reverse (13102105545301), we get a palindrome (23456655665432).

The spelling of 10354550120131 in words is "ten trillion, three hundred fifty-four billion, five hundred fifty million, one hundred twenty thousand, one hundred thirty-one".