Base | Representation |
---|---|
bin | 10111100010111001100101… |
… | …000110010010110000011001 |
3 | 111120122121022112122020110012 |
4 | 113202321211012102300121 |
5 | 102033104234024430230 |
6 | 1004123431125131305 |
7 | 30545324510643413 |
oct | 2742714506226031 |
9 | 446577275566405 |
10 | 103553357655065 |
11 | 2aaa480684733a |
12 | b745401b59b35 |
13 | 45a2069381476 |
14 | 1b8001b5659b3 |
15 | be89d917c395 |
hex | 5e2e65192c19 |
103553357655065 has 16 divisors (see below), whose sum is σ = 124432149182976. Its totient is φ = 82730610840000.
The previous prime is 103553357654941. The next prime is 103553357655103. The reversal of 103553357655065 is 560556753355301.
It is not a de Polignac number, because 103553357655065 - 210 = 103553357654041 is a prime.
It is a super-3 number, since 3×1035533576550653 (a number of 43 digits) contains 333 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 103553357654995 and 103553357655013.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 192516884 + ... + 193054026.
It is an arithmetic number, because the mean of its divisors is an integer number (7777009323936).
Almost surely, 2103553357655065 is an apocalyptic number.
It is an amenable number.
103553357655065 is a deficient number, since it is larger than the sum of its proper divisors (20878791527911).
103553357655065 is an equidigital number, since it uses as much as digits as its factorization.
103553357655065 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 589240.
The product of its (nonzero) digits is 106312500, while the sum is 59.
The spelling of 103553357655065 in words is "one hundred three trillion, five hundred fifty-three billion, three hundred fifty-seven million, six hundred fifty-five thousand, sixty-five".
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