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103678153441 = 992310448267
BaseRepresentation
bin110000010001110110…
…0110001001011100001
3100220121111201220012221
41200203230301023201
53144313101402231
6115343514351041
710330145522632
oct1404354611341
9326544656187
10103678153441
113aa73684235
121811572b481
139a138545b5
145037755889
152a6c0d7d11
hex1823b312e1

103678153441 has 4 divisors (see below), whose sum is σ = 103688611632. Its totient is φ = 103667695252.

The previous prime is 103678153427. The next prime is 103678153541. The reversal of 103678153441 is 144351876301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 144351876301 = 740171950253.

It is a cyclic number.

It is not a de Polignac number, because 103678153441 - 211 = 103678151393 is a prime.

It is a super-3 number, since 3×1036781534413 (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (103678153541) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5214211 + ... + 5234056.

It is an arithmetic number, because the mean of its divisors is an integer number (25922152908).

Almost surely, 2103678153441 is an apocalyptic number.

It is an amenable number.

103678153441 is a deficient number, since it is larger than the sum of its proper divisors (10458191).

103678153441 is an equidigital number, since it uses as much as digits as its factorization.

103678153441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10458190.

The product of its (nonzero) digits is 241920, while the sum is 43.

The spelling of 103678153441 in words is "one hundred three billion, six hundred seventy-eight million, one hundred fifty-three thousand, four hundred forty-one".

Divisors: 1 9923 10448267 103678153441