Base | Representation |
---|---|
bin | 1001011101010101000100… |
… | …1110010111011010000001 |
3 | 1100211011212112120220200001 |
4 | 2113111101032113122001 |
5 | 2330341113001402001 |
6 | 34041242100400001 |
7 | 2122223526056401 |
oct | 227252116273201 |
9 | 40734775526601 |
10 | 10399478544001 |
11 | 334a437584848 |
12 | 11bb5a43a6001 |
13 | 5a588873b701 |
14 | 27d4a1d52801 |
15 | 1307aab86001 |
hex | 97551397681 |
10399478544001 has 4 divisors (see below), whose sum is σ = 10399529606404. Its totient is φ = 10399427481600.
The previous prime is 10399478543917. The next prime is 10399478544023. The reversal of 10399478544001 is 10044587499301.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 9498421966401 + 901056577600 = 3081951^2 + 949240^2 .
It is a cyclic number.
It is not a de Polignac number, because 10399478544001 - 225 = 10399444989569 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10399478544031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25224480 + ... + 25633441.
It is an arithmetic number, because the mean of its divisors is an integer number (2599882401601).
Almost surely, 210399478544001 is an apocalyptic number.
It is an amenable number.
10399478544001 is a deficient number, since it is larger than the sum of its proper divisors (51062403).
10399478544001 is an equidigital number, since it uses as much as digits as its factorization.
10399478544001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 51062402.
The product of its (nonzero) digits is 4354560, while the sum is 55.
The spelling of 10399478544001 in words is "ten trillion, three hundred ninety-nine billion, four hundred seventy-eight million, five hundred forty-four thousand, one".
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