1040014113 has 4 divisors (see below), whose sum is σ = 1386685488. Its totient is φ = 693342740.

The previous prime is 1040014111. The next prime is 1040014123. The reversal of 1040014113 is 3114100401.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3114100401 = 3 ⋅1038033467.

It is a cyclic number.

It is not a de Polignac number, because 1040014113 - 2¹ = 1040014111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1040014092 and 1040014101.

It is not an unprimeable number, because it can be changed into a prime (1040014111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 173335683 + ... + 173335688.

It is an arithmetic number, because the mean of its divisors is an integer number (346671372).

Almost surely, 2^1040014113 is an apocalyptic number.

It is an amenable number.

1040014113 is a deficient number, since it is larger than the sum of its proper divisors (346671375).

1040014113 is an equidigital number, since it uses as much as digits as its factorization.

1040014113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 346671374.

The product of its (nonzero) digits is 48, while the sum is 15.

The square root of 1040014113 is about 32249.2498052280. The cubic root of 1040014113 is about 1013.1639867221.

Adding to 1040014113 its reverse (3114100401), we get a palindrome (4154114514).

The spelling of 1040014113 in words is "one billion, forty million, fourteen thousand, one hundred thirteen".