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104010113 = 105198963
BaseRepresentation
bin1100011001100…
…01000110000001
321020201021001102
412030301012001
5203111310423
614153144145
72402033324
oct614610601
9236637042
10104010113
1153790379
122a9bb055
1318718b5c
14db567bb
1591e7c28
hex6331181

104010113 has 4 divisors (see below), whose sum is σ = 104110128. Its totient is φ = 103910100.

The previous prime is 104010091. The next prime is 104010139. The reversal of 104010113 is 311010401.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 104010113 - 210 = 104009089 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 104010094 and 104010103.

It is not an unprimeable number, because it can be changed into a prime (104010143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48431 + ... + 50532.

It is an arithmetic number, because the mean of its divisors is an integer number (26027532).

Almost surely, 2104010113 is an apocalyptic number.

It is an amenable number.

104010113 is a deficient number, since it is larger than the sum of its proper divisors (100015).

104010113 is an equidigital number, since it uses as much as digits as its factorization.

104010113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 100014.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 104010113 is about 10198.5348457511. The cubic root of 104010113 is about 470.2821800294.

Adding to 104010113 its reverse (311010401), we get a palindrome (415020514).

The spelling of 104010113 in words is "one hundred four million, ten thousand, one hundred thirteen".

Divisors: 1 1051 98963 104010113