10401211433 has 4 divisors (see below), whose sum is σ = 10401505920. Its totient is φ = 10400916948.

The previous prime is 10401211417. The next prime is 10401211453. The reversal of 10401211433 is 33411210401.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33411210401 = 20899 ⋅1598699.

It is a cyclic number.

It is not a de Polignac number, because 10401211433 - 2⁴ = 10401211417 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (10401211453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85685 + ... + 167762.

It is an arithmetic number, because the mean of its divisors is an integer number (2600376480).

Almost surely, 2^10401211433 is an apocalyptic number.

It is an amenable number.

10401211433 is a deficient number, since it is larger than the sum of its proper divisors (294487).

10401211433 is an equidigital number, since it uses as much as digits as its factorization.

10401211433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 294486.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 10401211433 its reverse (33411210401), we get a palindrome (43812421834).

The spelling of 10401211433 in words is "ten billion, four hundred one million, two hundred eleven thousand, four hundred thirty-three".