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1040130003 = 31131519091
BaseRepresentation
bin111101111111110…
…001111111010011
32200111012002010110
4331333301333103
54112233130003
6251113332403
734526646663
oct7577617723
92614162113
101040130003
11494143080
12250407103
1313764ac53
149c1d61a3
15614aba03
hex3dff1fd3

1040130003 has 8 divisors (see below), whose sum is σ = 1512916416. Its totient is φ = 630381800.

The previous prime is 1040130001. The next prime is 1040130029. The reversal of 1040130003 is 3000310401.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1040130003 - 21 = 1040130001 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1040130001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15759513 + ... + 15759578.

It is an arithmetic number, because the mean of its divisors is an integer number (189114552).

Almost surely, 21040130003 is an apocalyptic number.

1040130003 is a deficient number, since it is larger than the sum of its proper divisors (472786413).

1040130003 is a wasteful number, since it uses less digits than its factorization.

1040130003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31519105.

The product of its (nonzero) digits is 36, while the sum is 12.

The square root of 1040130003 is about 32251.0465411589. The cubic root of 1040130003 is about 1013.2016180106.

Adding to 1040130003 its reverse (3000310401), we get a palindrome (4040440404).

It can be divided in two parts, 10401 and 30003, that added together give a palindrome (40404).

The spelling of 1040130003 in words is "one billion, forty million, one hundred thirty thousand, three".

Divisors: 1 3 11 33 31519091 94557273 346710001 1040130003