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10402124115 = 352923912929
BaseRepresentation
bin10011011000000001…
…11101000101010011
3222211221102122201010
421230000331011103
5132300420432430
64440105342003
7515526411315
oct115400750523
928757378633
1010402124115
114458800899
122023797903
13c9a0c3836
1470971b7b5
1540d340cb0
hex26c03d153

10402124115 has 16 divisors (see below), whose sum is σ = 17217309600. Its totient is φ = 5356495872.

The previous prime is 10402124107. The next prime is 10402124147. The reversal of 10402124115 is 51142120401.

It is not a de Polignac number, because 10402124115 - 23 = 10402124107 is a prime.

It is a super-2 number, since 2×104021241152 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10402124091 and 10402124100.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11956030 + ... + 11956899.

It is an arithmetic number, because the mean of its divisors is an integer number (1076081850).

Almost surely, 210402124115 is an apocalyptic number.

10402124115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

10402124115 is a deficient number, since it is larger than the sum of its proper divisors (6815185485).

10402124115 is a wasteful number, since it uses less digits than its factorization.

10402124115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23912966.

The product of its (nonzero) digits is 320, while the sum is 21.

Adding to 10402124115 its reverse (51142120401), we get a palindrome (61544244516).

The spelling of 10402124115 in words is "ten billion, four hundred two million, one hundred twenty-four thousand, one hundred fifteen".

Divisors: 1 3 5 15 29 87 145 435 23912929 71738787 119564645 358693935 693474941 2080424823 3467374705 10402124115