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1040315031323 = 1553996694477
BaseRepresentation
bin11110010001101111001…
…10111001111100011011
310200110020100021012201022
433020313212321330123
5114021031122000243
62113525241313055
7135105655602341
oct17106746717433
93613210235638
101040315031323
113712167946a7
1214975349578b
13771416ac869
14384cc7bb991
151c0dac2ab68
hexf2379b9f1b

1040315031323 has 4 divisors (see below), whose sum is σ = 1040321881200. Its totient is φ = 1040308181448.

The previous prime is 1040315031313. The next prime is 1040315031361. The reversal of 1040315031323 is 3231305130401.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1040315031323 - 222 = 1040310837019 is a prime.

It is a super-2 number, since 2×10403150313232 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1040315031292 and 1040315031301.

It is not an unprimeable number, because it can be changed into a prime (1040315031313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3191840 + ... + 3502637.

It is an arithmetic number, because the mean of its divisors is an integer number (260080470300).

Almost surely, 21040315031323 is an apocalyptic number.

1040315031323 is a deficient number, since it is larger than the sum of its proper divisors (6849877).

1040315031323 is an equidigital number, since it uses as much as digits as its factorization.

1040315031323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6849876.

The product of its (nonzero) digits is 3240, while the sum is 26.

The spelling of 1040315031323 in words is "one trillion, forty billion, three hundred fifteen million, thirty-one thousand, three hundred twenty-three".

Divisors: 1 155399 6694477 1040315031323