1040333120121 has 4 divisors (see below), whose sum is σ = 1387110826832. Its totient is φ = 693555413412.

The previous prime is 1040333120089. The next prime is 1040333120129. The reversal of 1040333120121 is 1210213330401.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1040333120121 - 2⁵ = 1040333120089 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1040333120129) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 173388853351 + ... + 173388853356.

It is an arithmetic number, because the mean of its divisors is an integer number (346777706708).

Almost surely, 2^{1040333120121} is an apocalyptic number.

It is an amenable number.

1040333120121 is a deficient number, since it is larger than the sum of its proper divisors (346777706711).

1040333120121 is an equidigital number, since it uses as much as digits as its factorization.

1040333120121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 346777706710.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 1040333120121 its reverse (1210213330401), we get a palindrome (2250546450522).

The spelling of 1040333120121 in words is "one trillion, forty billion, three hundred thirty-three million, one hundred twenty thousand, one hundred twenty-one".