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104043149113 = 293587694797
BaseRepresentation
bin110000011100101110…
…1000111011100111001
3100221112221112121011011
41200321131013130321
53201040021232423
6115444033433521
710342200114151
oct1407135073471
9327487477134
10104043149113
1140140710952
12181b7a0b8a1
139a7135b177
145070007761
152a8e184b0d
hex1839747739

104043149113 has 4 divisors (see below), whose sum is σ = 107630843940. Its totient is φ = 100455454288.

The previous prime is 104043148991. The next prime is 104043149143. The reversal of 104043149113 is 311941340401.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 311941340401 = 1701791833019.

It can be written as a sum of positive squares in 2 ways, for example, as 41389054249 + 62654094864 = 203443^2 + 250308^2 .

It is a cyclic number.

It is not a de Polignac number, because 104043149113 - 217 = 104043018041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (104043149143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1793847370 + ... + 1793847427.

It is an arithmetic number, because the mean of its divisors is an integer number (26907710985).

Almost surely, 2104043149113 is an apocalyptic number.

It is an amenable number.

104043149113 is a deficient number, since it is larger than the sum of its proper divisors (3587694827).

104043149113 is an equidigital number, since it uses as much as digits as its factorization.

104043149113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3587694826.

The product of its (nonzero) digits is 5184, while the sum is 31.

Adding to 104043149113 its reverse (311941340401), we get a palindrome (415984489514).

The spelling of 104043149113 in words is "one hundred four billion, forty-three million, one hundred forty-nine thousand, one hundred thirteen".

Divisors: 1 29 3587694797 104043149113