Base | Representation |
---|---|
bin | 10011011000010010… |
… | …11010111010001001 |
3 | 222212002121102001002 |
4 | 21230021122322021 |
5 | 132302002442213 |
6 | 4440225104345 |
7 | 515554313531 |
oct | 115411327211 |
9 | 28762542032 |
10 | 10404343433 |
11 | 4459a87240 |
12 | 20244880b5 |
13 | c9a6bca43 |
14 | 709b384c1 |
15 | 40d62d658 |
hex | 26c25ae89 |
10404343433 has 4 divisors (see below), whose sum is σ = 11350192848. Its totient is φ = 9458494020.
The previous prime is 10404343421. The next prime is 10404343459. The reversal of 10404343433 is 33434340401.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 10404343433 - 214 = 10404327049 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 10404343396 and 10404343405.
It is not an unprimeable number, because it can be changed into a prime (10404343403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 472924691 + ... + 472924712.
It is an arithmetic number, because the mean of its divisors is an integer number (2837548212).
Almost surely, 210404343433 is an apocalyptic number.
It is an amenable number.
10404343433 is a deficient number, since it is larger than the sum of its proper divisors (945849415).
10404343433 is an equidigital number, since it uses as much as digits as its factorization.
10404343433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 945849414.
The product of its (nonzero) digits is 20736, while the sum is 29.
Adding to 10404343433 its reverse (33434340401), we get a palindrome (43838683834).
The spelling of 10404343433 in words is "ten billion, four hundred four million, three hundred forty-three thousand, four hundred thirty-three".
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