Base | Representation |
---|---|
bin | 10111101010001000100001… |
… | …001000010100010100011011 |
3 | 111122102010100121121120211201 |
4 | 113222020201020110110123 |
5 | 102114230241441311103 |
6 | 1005144035334335031 |
7 | 30626252512161256 |
oct | 2752104110242433 |
9 | 448363317546751 |
10 | 104050433541403 |
11 | 301765a5165978 |
12 | b8058077ba477 |
13 | 4609bb576786b |
14 | 1b9a0d429809d |
15 | c068cd20b51d |
hex | 5ea22121451b |
104050433541403 has 16 divisors (see below), whose sum is σ = 104564498987520. Its totient is φ = 103537758528000.
The previous prime is 104050433541349. The next prime is 104050433541413. The reversal of 104050433541403 is 304145334050401.
It is a cyclic number.
It is not a de Polignac number, because 104050433541403 - 29 = 104050433540891 is a prime.
It is not an unprimeable number, because it can be changed into a prime (104050433541413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 522827451 + ... + 523026427.
It is an arithmetic number, because the mean of its divisors is an integer number (6535281186720).
Almost surely, 2104050433541403 is an apocalyptic number.
104050433541403 is a deficient number, since it is larger than the sum of its proper divisors (514065446117).
104050433541403 is a wasteful number, since it uses less digits than its factorization.
104050433541403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 202458.
The product of its (nonzero) digits is 172800, while the sum is 37.
Adding to 104050433541403 its reverse (304145334050401), we get a palindrome (408195767591804).
The spelling of 104050433541403 in words is "one hundred four trillion, fifty billion, four hundred thirty-three million, five hundred forty-one thousand, four hundred three".
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