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1041132003011 = 8929311659727
BaseRepresentation
bin11110010011010000100…
…11011001111011000011
310200112100021112200011222
433021220103121323003
5114024214243044021
62114142304025255
7135135136003112
oct17115023317303
93615307480158
101041132003011
113715a5967611
1214994100222b
1377241a25669
14385690c3c79
151c1378066ab
hexf2684d9ec3

1041132003011 has 4 divisors (see below), whose sum is σ = 1041143752032. Its totient is φ = 1041120253992.

The previous prime is 1041132003007. The next prime is 1041132003139. The reversal of 1041132003011 is 1103002311401.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1041132003011 - 22 = 1041132003007 is a prime.

It is a super-2 number, since 2×10411320030112 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1041132003811) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5740571 + ... + 5919156.

It is an arithmetic number, because the mean of its divisors is an integer number (260285938008).

Almost surely, 21041132003011 is an apocalyptic number.

1041132003011 is a deficient number, since it is larger than the sum of its proper divisors (11749021).

1041132003011 is an equidigital number, since it uses as much as digits as its factorization.

1041132003011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11749020.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1041132003011 its reverse (1103002311401), we get a palindrome (2144134314412).

The spelling of 1041132003011 in words is "one trillion, forty-one billion, one hundred thirty-two million, three thousand, eleven".

Divisors: 1 89293 11659727 1041132003011