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10411353131 = 31772343487
BaseRepresentation
bin10011011001001000…
…01010010000101011
3222212120210112112112
421230210022100223
5132310301300011
64441035232535
7516001020134
oct115444122053
928776715475
1010411353131
114462a34783
1220268a874b
13c9bca54aa
1470aa40c8b
1540e06558b
hex26c90a42b

10411353131 has 8 divisors (see below), whose sum is σ = 10748841984. Its totient is φ = 10073966760.

The previous prime is 10411353103. The next prime is 10411353137. The reversal of 10411353131 is 13135311401.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10411353131 is a prime.

It is a super-2 number, since 2×104113531312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10411353097 and 10411353106.

It is not an unprimeable number, because it can be changed into a prime (10411353137) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 217670 + ... + 261156.

It is an arithmetic number, because the mean of its divisors is an integer number (1343605248).

Almost surely, 210411353131 is an apocalyptic number.

10411353131 is a deficient number, since it is larger than the sum of its proper divisors (337488853).

10411353131 is an equidigital number, since it uses as much as digits as its factorization.

10411353131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51241.

The product of its (nonzero) digits is 540, while the sum is 23.

Adding to 10411353131 its reverse (13135311401), we get a palindrome (23546664532).

The spelling of 10411353131 in words is "ten billion, four hundred eleven million, three hundred fifty-three thousand, one hundred thirty-one".

Divisors: 1 31 7723 43487 239413 1348097 335850101 10411353131