10412103131433 has 12 divisors (see below), whose sum is σ = 15406526585268. Its totient is φ = 6772099597440.

The previous prime is 10412103131407. The next prime is 10412103131467. The reversal of 10412103131433 is 33413130121401.

10412103131433 is a `hidden beast` number, since 1 + 0 + 4 + 1 + 210 + 3 + 13 + 1 + 433 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 5574377664144 + 4837725467289 = 2361012^2 + 2199483^2 .

It is not a de Polignac number, because 10412103131433 - 2²¹ = 10412101034281 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10412103131397 and 10412103131406.

It is not an unprimeable number, because it can be changed into a prime (10412103131333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 14108540460 + ... + 14108541197.

It is an arithmetic number, because the mean of its divisors is an integer number (1283877215439).

Almost surely, 2^{10412103131433} is an apocalyptic number.

It is an amenable number.

10412103131433 is a deficient number, since it is larger than the sum of its proper divisors (4994423453835).

10412103131433 is a wasteful number, since it uses less digits than its factorization.

10412103131433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28217081704 (or 28217081701 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 27.

Adding to 10412103131433 its reverse (33413130121401), we get a palindrome (43825233252834).

The spelling of 10412103131433 in words is "ten trillion, four hundred twelve billion, one hundred three million, one hundred thirty-one thousand, four hundred thirty-three".