Base | Representation |
---|---|
bin | 10011011001001110… |
… | …00110000101000001 |
3 | 222212122020121211012 |
4 | 21230213012011001 |
5 | 132311000404213 |
6 | 4441103530305 |
7 | 516010403036 |
oct | 115447060501 |
9 | 28778217735 |
10 | 10412122433 |
11 | 446340a769 |
12 | 2026bb9995 |
13 | c9c1b46bb |
14 | 70aba138d |
15 | 40e1684a8 |
hex | 26c9c6141 |
10412122433 has 4 divisors (see below), whose sum is σ = 10413085380. Its totient is φ = 10411159488.
The previous prime is 10412122429. The next prime is 10412122459. The reversal of 10412122433 is 33422121401.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 10030623409 + 381499024 = 100153^2 + 19532^2 .
It is a cyclic number.
It is not a de Polignac number, because 10412122433 - 22 = 10412122429 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 10412122399 and 10412122408.
It is not an unprimeable number, because it can be changed into a prime (10412122423) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 465068 + ... + 486941.
It is an arithmetic number, because the mean of its divisors is an integer number (2603271345).
Almost surely, 210412122433 is an apocalyptic number.
It is an amenable number.
10412122433 is a deficient number, since it is larger than the sum of its proper divisors (962947).
10412122433 is an equidigital number, since it uses as much as digits as its factorization.
10412122433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 962946.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 10412122433 its reverse (33422121401), we get a palindrome (43834243834).
The spelling of 10412122433 in words is "ten billion, four hundred twelve million, one hundred twenty-two thousand, four hundred thirty-three".
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