10413043331 has 4 divisors (see below), whose sum is σ = 10426275432. Its totient is φ = 10399811232.

The previous prime is 10413043327. The next prime is 10413043363. The reversal of 10413043331 is 13334031401.

10413043331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13334031401 = 2131 ⋅6257171.

It is a cyclic number.

It is not a de Polignac number, because 10413043331 - 2² = 10413043327 is a prime.

It is a super-2 number, since 2×10413043331² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10413043297 and 10413043306.

It is not an unprimeable number, because it can be changed into a prime (10413043831) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6614870 + ... + 6616443.

It is an arithmetic number, because the mean of its divisors is an integer number (2606568858).

Almost surely, 2^10413043331 is an apocalyptic number.

10413043331 is a deficient number, since it is larger than the sum of its proper divisors (13232101).

10413043331 is an equidigital number, since it uses as much as digits as its factorization.

10413043331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13232100.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 10413043331 its reverse (13334031401), we get a palindrome (23747074732).

The spelling of 10413043331 in words is "ten billion, four hundred thirteen million, forty-three thousand, three hundred thirty-one".