10413141113 has 4 divisors (see below), whose sum is σ = 10413797520. Its totient is φ = 10412484708.

The previous prime is 10413141077. The next prime is 10413141119. The reversal of 10413141113 is 31114131401.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10413141113 - 2¹⁸ = 10412878969 is a prime.

It is a super-3 number, since 3×10413141113³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10413141119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 303803 + ... + 336336.

It is an arithmetic number, because the mean of its divisors is an integer number (2603449380).

Almost surely, 2^10413141113 is an apocalyptic number.

It is an amenable number.

10413141113 is a deficient number, since it is larger than the sum of its proper divisors (656407).

10413141113 is an equidigital number, since it uses as much as digits as its factorization.

10413141113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 656406.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 10413141113 its reverse (31114131401), we get a palindrome (41527272514).

The spelling of 10413141113 in words is "ten billion, four hundred thirteen million, one hundred forty-one thousand, one hundred thirteen".