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10414115 = 51727207
BaseRepresentation
bin100111101110…
…100000100011
3201121002110222
4213232200203
510131222430
61011113255
7154342565
oct47564043
921532428
1010414115
115973308
1235a282b
1322081ca
141551335
15daa9e5
hex9ee823

10414115 has 12 divisors (see below), whose sum is σ = 13277136. Its totient is φ = 7840128.

The previous prime is 10414097. The next prime is 10414133. The reversal of 10414115 is 51141401.

10414115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (10414097) and next prime (10414133).

It is not a de Polignac number, because 10414115 - 216 = 10348579 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (17).

It is a junction number, because it is equal to n+sod(n) for n = 10414093 and 10414102.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2159 + ... + 5048.

It is an arithmetic number, because the mean of its divisors is an integer number (1106428).

Almost surely, 210414115 is an apocalyptic number.

10414115 is a deficient number, since it is larger than the sum of its proper divisors (2863021).

10414115 is an equidigital number, since it uses as much as digits as its factorization.

10414115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7246 (or 7229 counting only the distinct ones).

The product of its (nonzero) digits is 80, while the sum is 17.

The square root of 10414115 is about 3227.0907951280. The cubic root of 10414115 is about 218.3772820386.

Adding to 10414115 its reverse (51141401), we get a palindrome (61555516).

The spelling of 10414115 in words is "ten million, four hundred fourteen thousand, one hundred fifteen".

Divisors: 1 5 17 85 289 1445 7207 36035 122519 612595 2082823 10414115