Base | Representation |
---|---|
bin | 11110010011110010001… |
… | …00001001000000101011 |
3 | 10200120001212200200111002 |
4 | 33021321010021000223 |
5 | 114030303240324001 |
6 | 2114230231225215 |
7 | 135145122160004 |
oct | 17117104110053 |
9 | 3616055620432 |
10 | 1041413214251 |
11 | 37172a6787a3 |
12 | 1499bb21820b |
13 | 77288075447 |
14 | 385945a61ab |
15 | 1c15235346b |
hex | f27910902b |
1041413214251 has 4 divisors (see below), whose sum is σ = 1041415960992. Its totient is φ = 1041410467512.
The previous prime is 1041413214221. The next prime is 1041413214253. The reversal of 1041413214251 is 1524123141401.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1041413214251 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1041413214253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 691955 + ... + 1600508.
It is an arithmetic number, because the mean of its divisors is an integer number (260353990248).
Almost surely, 21041413214251 is an apocalyptic number.
1041413214251 is a deficient number, since it is larger than the sum of its proper divisors (2746741).
1041413214251 is an equidigital number, since it uses as much as digits as its factorization.
1041413214251 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2746740.
The product of its (nonzero) digits is 3840, while the sum is 29.
Adding to 1041413214251 its reverse (1524123141401), we get a palindrome (2565536355652).
The spelling of 1041413214251 in words is "one trillion, forty-one billion, four hundred thirteen million, two hundred fourteen thousand, two hundred fifty-one".
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