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1042300051 = 1380176927
BaseRepresentation
bin111110001000000…
…011110010010011
32200122021022212121
4332020003302103
54113312100201
6251232035111
734554255442
oct7610036223
92618238777
101042300051
11495395501
12251092a97
13137c2a8c0
149c5dcd59
15617899a1
hex3e203c93

1042300051 has 4 divisors (see below), whose sum is σ = 1122476992. Its totient is φ = 962123112.

The previous prime is 1042300033. The next prime is 1042300057. The reversal of 1042300051 is 1500032401.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1042300051 - 25 = 1042300019 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1042299998 and 1042300034.

It is not an unprimeable number, because it can be changed into a prime (1042300057) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40088451 + ... + 40088476.

It is an arithmetic number, because the mean of its divisors is an integer number (280619248).

Almost surely, 21042300051 is an apocalyptic number.

1042300051 is a deficient number, since it is larger than the sum of its proper divisors (80176941).

1042300051 is an equidigital number, since it uses as much as digits as its factorization.

1042300051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 80176940.

The product of its (nonzero) digits is 120, while the sum is 16.

The square root of 1042300051 is about 32284.6720751505. The cubic root of 1042300051 is about 1013.9057507774.

Adding to 1042300051 its reverse (1500032401), we get a palindrome (2542332452).

The spelling of 1042300051 in words is "one billion, forty-two million, three hundred thousand, fifty-one".

Divisors: 1 13 80176927 1042300051