10424010040131 has 16 divisors (see below), whose sum is σ = 13908846182400. Its totient is φ = 6944258065248.

The previous prime is 10424010040127. The next prime is 10424010040133. The reversal of 10424010040131 is 13104001042401.

10424010040131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 10424010040131 - 2² = 10424010040127 is a prime.

It is a super-3 number, since 3×10424010040131³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 10424010040098 and 10424010040107.

It is not an unprimeable number, because it can be changed into a prime (10424010040133) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 39019710 + ... + 39285948.

It is an arithmetic number, because the mean of its divisors is an integer number (869302886400).

Almost surely, 2^{10424010040131} is an apocalyptic number.

10424010040131 is a deficient number, since it is larger than the sum of its proper divisors (3484836142269).

10424010040131 is a wasteful number, since it uses less digits than its factorization.

10424010040131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 275738.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 10424010040131 its reverse (13104001042401), we get a palindrome (23528011082532).

The spelling of 10424010040131 in words is "ten trillion, four hundred twenty-four billion, ten million, forty thousand, one hundred thirty-one".