104333013041 has 4 divisors (see below), whose sum is σ = 104334821184. Its totient is φ = 104331204900.

The previous prime is 104333013019. The next prime is 104333013049. The reversal of 104333013041 is 140310333401.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 104333013041 - 2¹⁴ = 104332996657 is a prime.

It is a super-2 number, since 2×104333013041² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 104333012998 and 104333013016.

It is not an unprimeable number, because it can be changed into a prime (104333013049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 814565 + ... + 933906.

It is an arithmetic number, because the mean of its divisors is an integer number (26083705296).

Almost surely, 2^104333013041 is an apocalyptic number.

It is an amenable number.

104333013041 is a deficient number, since it is larger than the sum of its proper divisors (1808143).

104333013041 is an equidigital number, since it uses as much as digits as its factorization.

104333013041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1808142.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 104333013041 its reverse (140310333401), we get a palindrome (244643346442).

The spelling of 104333013041 in words is "one hundred four billion, three hundred thirty-three million, thirteen thousand, forty-one".