1043913403 has 4 divisors (see below), whose sum is σ = 1124214448. Its totient is φ = 963612360.

The previous prime is 1043913401. The next prime is 1043913413. The reversal of 1043913403 is 3043193401.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3043193401 = 103 ⋅29545567.

It is a cyclic number.

It is not a de Polignac number, because 1043913403 - 2¹ = 1043913401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1043913401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40150503 + ... + 40150528.

It is an arithmetic number, because the mean of its divisors is an integer number (281053612).

Almost surely, 2^1043913403 is an apocalyptic number.

1043913403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1043913403 is a deficient number, since it is larger than the sum of its proper divisors (80301045).

1043913403 is an equidigital number, since it uses as much as digits as its factorization.

1043913403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 80301044.

The product of its (nonzero) digits is 3888, while the sum is 28.

The square root of 1043913403 is about 32309.6487600840. The cubic root of 1043913403 is about 1014.4286148015.

The spelling of 1043913403 in words is "one billion, forty-three million, nine hundred thirteen thousand, four hundred three".