Search a number
-
+
10445525314113 = 39221377599151
BaseRepresentation
bin1001100000000000100111…
…0100110110101001000001
31100222120201121201012101010
42120000021310312221001
52332114413440022423
634114335202431133
72125443566131521
oct230001164665101
940876647635333
1010445525314113
113367a167a875a
1212084b53624a9
135aa016483c46
142817cd625681
15131aa3443693
hex98009d36a41

10445525314113 has 8 divisors (see below), whose sum is σ = 13928877518976. Its totient is φ = 6962928326000.

The previous prime is 10445525314109. The next prime is 10445525314243. The reversal of 10445525314113 is 31141352554401.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10445525314113 - 22 = 10445525314109 is a prime.

It is not an unprimeable number, because it can be changed into a prime (10445525314513) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 188771913 + ... + 188827238.

It is an arithmetic number, because the mean of its divisors is an integer number (1741109689872).

Almost surely, 210445525314113 is an apocalyptic number.

It is an amenable number.

10445525314113 is a deficient number, since it is larger than the sum of its proper divisors (3483352204863).

10445525314113 is an equidigital number, since it uses as much as digits as its factorization.

10445525314113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 377608375.

The product of its (nonzero) digits is 144000, while the sum is 39.

Adding to 10445525314113 its reverse (31141352554401), we get a palindrome (41586877868514).

The spelling of 10445525314113 in words is "ten trillion, four hundred forty-five billion, five hundred twenty-five million, three hundred fourteen thousand, one hundred thirteen".

Divisors: 1 3 9221 27663 377599151 1132797453 3481841771371 10445525314113