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105012237403 = 412561274083
BaseRepresentation
bin110000111001100110…
…1111001010001011011
3101001001111001101101001
41201303031321101123
53210031113044103
6120124132405431
710405205201353
oct1416315712133
9331044041331
10105012237403
1140598741267
1218428476877
139b970643a8
1451229c9b63
152ae92ac01d
hex187337945b

105012237403 has 4 divisors (see below), whose sum is σ = 107573511528. Its totient is φ = 102450963280.

The previous prime is 105012237329. The next prime is 105012237413. The reversal of 105012237403 is 304732210501.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 105012237403 - 29 = 105012236891 is a prime.

It is a super-2 number, since 2×1050122374032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (105012237413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1280637001 + ... + 1280637082.

It is an arithmetic number, because the mean of its divisors is an integer number (26893377882).

Almost surely, 2105012237403 is an apocalyptic number.

105012237403 is a deficient number, since it is larger than the sum of its proper divisors (2561274125).

105012237403 is an equidigital number, since it uses as much as digits as its factorization.

105012237403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2561274124.

The product of its (nonzero) digits is 5040, while the sum is 28.

Adding to 105012237403 its reverse (304732210501), we get a palindrome (409744447904).

The spelling of 105012237403 in words is "one hundred five billion, twelve million, two hundred thirty-seven thousand, four hundred three".

Divisors: 1 41 2561274083 105012237403