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1050132115 = 51151182473
BaseRepresentation
bin111110100101111…
…011111010010011
32201012000020110001
4332211323322103
54122313211430
6252111550431
735010655444
oct7645737223
92635006401
101050132115
1149985488a
1225382b417
13139740766
149d67b2cb
15622d53ca
hex3e97be93

1050132115 has 8 divisors (see below), whose sum is σ = 1261260288. Its totient is φ = 839371200.

The previous prime is 1050132077. The next prime is 1050132119. The reversal of 1050132115 is 5112310501.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1050132115 - 213 = 1050123923 is a prime.

It is a super-2 number, since 2×10501321152 = 2205554917908746450, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1050132092 and 1050132101.

It is not an unprimeable number, because it can be changed into a prime (1050132119) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 85482 + ... + 96991.

It is an arithmetic number, because the mean of its divisors is an integer number (157657536).

Almost surely, 21050132115 is an apocalyptic number.

1050132115 is a deficient number, since it is larger than the sum of its proper divisors (211128173).

1050132115 is a wasteful number, since it uses less digits than its factorization.

1050132115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 183629.

The product of its (nonzero) digits is 150, while the sum is 19.

The square root of 1050132115 is about 32405.7420066259. The cubic root of 1050132115 is about 1016.4389839809.

Adding to 1050132115 its reverse (5112310501), we get a palindrome (6162442616).

The spelling of 1050132115 in words is "one billion, fifty million, one hundred thirty-two thousand, one hundred fifteen".

Divisors: 1 5 1151 5755 182473 912365 210026423 1050132115