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10513131105 = 35700875407
BaseRepresentation
bin10011100101010000…
…11010011001100001
31000010200022101200010
421302220122121201
5133012330143410
64455112515133
7521345066001
oct116250323141
930120271603
1010513131105
114505430004
1220549abaa9
13cb70bc349
1471a376001
15417e6bc20
hex272a1a661

10513131105 has 8 divisors (see below), whose sum is σ = 16821009792. Its totient is φ = 5607003248.

The previous prime is 10513131067. The next prime is 10513131149. The reversal of 10513131105 is 50113131501.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10513131105 - 210 = 10513130081 is a prime.

It is a super-2 number, since 2×105131311052 (a number of 21 digits) contains 22 as substring.

It is a Curzon number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 350437689 + ... + 350437718.

It is an arithmetic number, because the mean of its divisors is an integer number (2102626224).

Almost surely, 210513131105 is an apocalyptic number.

10513131105 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

10513131105 is a deficient number, since it is larger than the sum of its proper divisors (6307878687).

10513131105 is an equidigital number, since it uses as much as digits as its factorization.

10513131105 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 700875415.

The product of its (nonzero) digits is 225, while the sum is 21.

Adding to 10513131105 its reverse (50113131501), we get a palindrome (60626262606).

The spelling of 10513131105 in words is "ten billion, five hundred thirteen million, one hundred thirty-one thousand, one hundred five".

Divisors: 1 3 5 15 700875407 2102626221 3504377035 10513131105