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105132253254051 = 3101934390661843
BaseRepresentation
bin10111111001111000000010…
…100111000001000110100011
3111210020112201111021001210110
4113321320002213001012203
5102234441323313112201
61011333031305302403
731100361146050512
oct2771700247010643
9453215644231713
10105132253254051
113055337a1959a1
12b95b402a94a03
134687c0cb6a94a
141bd65dd004679
15c24ae7a906d6
hex5f9e029c11a3

105132253254051 has 8 divisors (see below), whose sum is σ = 140313900323520. Its totient is φ = 70019387510312.

The previous prime is 105132253254031. The next prime is 105132253254053. The reversal of 105132253254051 is 150452352231501.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 105132253254051 - 211 = 105132253252003 is a prime.

It is a super-2 number, since 2×1051322532540512 (a number of 29 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (105132253254053) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17195327865 + ... + 17195333978.

It is an arithmetic number, because the mean of its divisors is an integer number (17539237540440).

Almost surely, 2105132253254051 is an apocalyptic number.

105132253254051 is a deficient number, since it is larger than the sum of its proper divisors (35181647069469).

105132253254051 is a wasteful number, since it uses less digits than its factorization.

105132253254051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34390662865.

The product of its (nonzero) digits is 180000, while the sum is 39.

The spelling of 105132253254051 in words is "one hundred five trillion, one hundred thirty-two billion, two hundred fifty-three million, two hundred fifty-four thousand, fifty-one".

Divisors: 1 3 1019 3057 34390661843 103171985529 35044084418017 105132253254051