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105214253147 = 7313910369001
BaseRepresentation
bin110000111111101000…
…0100001100001011011
3101001120120011211212122
41201333100201201123
53210434322100042
6120200150331455
710413210252503
oct1417720414133
9331516154778
10105214253147
1140691780723
1218484059b8b
139bc9b76033
145141774a03
152b0bdb37d2
hex187f42185b

105214253147 has 8 divisors (see below), whose sum is σ = 107422860720. Its totient is φ = 103026384000.

The previous prime is 105214253101. The next prime is 105214253153. The reversal of 105214253147 is 741352412501.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 105214253147 - 214 = 105214236763 is a prime.

It is a super-2 number, since 2×1052142531472 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (105214253197) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5174354 + ... + 5194647.

It is an arithmetic number, because the mean of its divisors is an integer number (13427857590).

Almost surely, 2105214253147 is an apocalyptic number.

105214253147 is a deficient number, since it is larger than the sum of its proper divisors (2208607573).

105214253147 is a wasteful number, since it uses less digits than its factorization.

105214253147 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10369213.

The product of its (nonzero) digits is 33600, while the sum is 35.

Adding to 105214253147 its reverse (741352412501), we get a palindrome (846566665648).

The spelling of 105214253147 in words is "one hundred five billion, two hundred fourteen million, two hundred fifty-three thousand, one hundred forty-seven".

Divisors: 1 73 139 10147 10369001 756937073 1441291139 105214253147