Base | Representation |
---|---|
bin | 101000001000… |
… | …101101011001 |
3 | 201210112200201 |
4 | 220020231121 |
5 | 10143141213 |
6 | 1013302201 |
7 | 155300506 |
oct | 50105531 |
9 | 21715621 |
10 | 10521433 |
11 | 5a369aa |
12 | 3634961 |
13 | 2245000 |
14 | 157c4ad |
15 | dcc6dd |
hex | a08b59 |
10521433 has 8 divisors (see below), whose sum is σ = 11400200. Its totient is φ = 9710064.
The previous prime is 10521377. The next prime is 10521437. The reversal of 10521433 is 33412501.
10521433 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 4 ways, for example, as 5890329 + 4631104 = 2427^2 + 2152^2 .
It is not a de Polignac number, because 10521433 - 217 = 10390361 is a prime.
It is a super-2 number, since 2×105214332 = 221401104746978, which contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 10521433.
It is not an unprimeable number, because it can be changed into a prime (10521437) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 198 + ... + 4591.
It is an arithmetic number, because the mean of its divisors is an integer number (1425025).
Almost surely, 210521433 is an apocalyptic number.
10521433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
10521433 is a deficient number, since it is larger than the sum of its proper divisors (878767).
10521433 is an frugal number, since it uses more digits than its factorization.
10521433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4828 (or 4802 counting only the distinct ones).
The product of its (nonzero) digits is 360, while the sum is 19.
The square root of 10521433 is about 3243.6758469366. The cubic root of 10521433 is about 219.1248497536.
Adding to 10521433 its reverse (33412501), we get a palindrome (43933934).
It can be divided in two parts, 1052 and 1433, that added together give a triangular number (2485 = T70).
The spelling of 10521433 in words is "ten million, five hundred twenty-one thousand, four hundred thirty-three".
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