Base | Representation |
---|---|
bin | 1001100100100101110100… |
… | …1111001010111101101011 |
3 | 1101021002212222020111100112 |
4 | 2121021131033022331223 |
5 | 2334412112414231410 |
6 | 34214433313524535 |
7 | 2134231222063655 |
oct | 231113517127553 |
9 | 41232788214315 |
10 | 10524234133355 |
11 | 33983368905a8 |
12 | 121b80087374b |
13 | 5b457ac4b077 |
14 | 285538ad76d5 |
15 | 133b5d3b5105 |
hex | 9925d3caf6b |
10524234133355 has 8 divisors (see below), whose sum is σ = 12629155057200. Its totient is φ = 8419337908576.
The previous prime is 10524234133261. The next prime is 10524234133403. The reversal of 10524234133355 is 55333143242501.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 10524234133355 - 218 = 10524233871211 is a prime.
It is a super-2 number, since 2×105242341333552 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5224040 + ... + 6952629.
It is an arithmetic number, because the mean of its divisors is an integer number (1578644382150).
Almost surely, 210524234133355 is an apocalyptic number.
10524234133355 is a deficient number, since it is larger than the sum of its proper divisors (2104920923845).
10524234133355 is a wasteful number, since it uses less digits than its factorization.
10524234133355 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12349533.
The product of its (nonzero) digits is 648000, while the sum is 41.
Adding to 10524234133355 its reverse (55333143242501), we get a palindrome (65857377375856).
The spelling of 10524234133355 in words is "ten trillion, five hundred twenty-four billion, two hundred thirty-four million, one hundred thirty-three thousand, three hundred fifty-five".
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