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1053101122113 = 32912487969377
BaseRepresentation
bin11110101001100011011…
…01111110001001000001
310201200020102112220220110
433110301231332021001
5114223222341401423
62123442111501533
7136040553562065
oct17246155761101
93650212486813
101053101122113
11376688146987
121501215278a9
13783cb667261
1438d82983aa5
151c5d84c7193
hexf531b7e241

1053101122113 has 16 divisors (see below), whose sum is σ = 1452671095680. Its totient is φ = 677803209216.

The previous prime is 1053101122043. The next prime is 1053101122123. The reversal of 1053101122113 is 3112211013501.

It is not a de Polignac number, because 1053101122113 - 213 = 1053101113921 is a prime.

It is a super-2 number, since 2×10531011221132 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1053101122113.

It is not an unprimeable number, because it can be changed into a prime (1053101122123) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 601681 + ... + 1571057.

It is an arithmetic number, because the mean of its divisors is an integer number (90791943480).

Almost surely, 21053101122113 is an apocalyptic number.

It is an amenable number.

1053101122113 is a deficient number, since it is larger than the sum of its proper divisors (399569973567).

1053101122113 is a wasteful number, since it uses less digits than its factorization.

1053101122113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 981896.

The product of its (nonzero) digits is 180, while the sum is 21.

Adding to 1053101122113 its reverse (3112211013501), we get a palindrome (4165312135614).

The spelling of 1053101122113 in words is "one trillion, fifty-three billion, one hundred one million, one hundred twenty-two thousand, one hundred thirteen".

Divisors: 1 3 29 87 12487 37461 362123 969377 1086369 2908131 28111933 84335799 12104610599 36313831797 351033707371 1053101122113