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1053130051 = 9781107671
BaseRepresentation
bin111110110001010…
…111110101000011
32201101122112211201
4332301113311003
54124100130201
6252300122031
735045313001
oct7661276503
92641575751
101053130051
114a0512216
12254836317
1313a25019c
149dc1ba71
15626c8801
hex3ec57d43

1053130051 has 4 divisors (see below), whose sum is σ = 1053247504. Its totient is φ = 1053012600.

The previous prime is 1053130031. The next prime is 1053130069. The reversal of 1053130051 is 1500313501.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1053130051 - 225 = 1019575619 is a prime.

It is a super-2 number, since 2×10531300512 = 2218165808638525202, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1053130031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44055 + ... + 63616.

It is an arithmetic number, because the mean of its divisors is an integer number (263311876).

Almost surely, 21053130051 is an apocalyptic number.

1053130051 is a deficient number, since it is larger than the sum of its proper divisors (117453).

1053130051 is an equidigital number, since it uses as much as digits as its factorization.

1053130051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 117452.

The product of its (nonzero) digits is 225, while the sum is 19.

The square root of 1053130051 is about 32451.9652871748. The cubic root of 1053130051 is about 1017.4053144127.

Adding to 1053130051 its reverse (1500313501), we get a palindrome (2553443552).

The spelling of 1053130051 in words is "one billion, fifty-three million, one hundred thirty thousand, fifty-one".

Divisors: 1 9781 107671 1053130051