1053143362201 has 4 divisors (see below), whose sum is σ = 1203592413952. Its totient is φ = 902694310452.

The previous prime is 1053143362199. The next prime is 1053143362207. The reversal of 1053143362201 is 1022633413501.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1053143362201 - 2¹ = 1053143362199 is a prime.

It is a super-3 number, since 3×1053143362201³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1053143362207) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 75224525865 + ... + 75224525878.

It is an arithmetic number, because the mean of its divisors is an integer number (300898103488).

Almost surely, 2^{1053143362201} is an apocalyptic number.

It is an amenable number.

1053143362201 is a deficient number, since it is larger than the sum of its proper divisors (150449051751).

1053143362201 is an equidigital number, since it uses as much as digits as its factorization.

1053143362201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 150449051750.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 1053143362201 its reverse (1022633413501), we get a palindrome (2075776775702).

The spelling of 1053143362201 in words is "one trillion, fifty-three billion, one hundred forty-three million, three hundred sixty-two thousand, two hundred one".