1053291433 has 4 divisors (see below), whose sum is σ = 1087268608. Its totient is φ = 1019314260.

The previous prime is 1053291401. The next prime is 1053291451. The reversal of 1053291433 is 3341923501.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3341923501 = 7 ⋅477417643.

It is a cyclic number.

It is not a de Polignac number, because 1053291433 - 2⁵ = 1053291401 is a prime.

It is a super-2 number, since 2×1053291433² = 2218845685662386978, which contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (31), and also a Moran number because the ratio is a prime number: 33977143 = 1053291433 / (1 + 0 + 5 + 3 + 2 + 9 + 1 + 4 + 3 + 3).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1053291395 and 1053291404.

It is not an unprimeable number, because it can be changed into a prime (1053291133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16988541 + ... + 16988602.

It is an arithmetic number, because the mean of its divisors is an integer number (271817152).

Almost surely, 2^1053291433 is an apocalyptic number.

It is an amenable number.

1053291433 is a deficient number, since it is larger than the sum of its proper divisors (33977175).

1053291433 is an equidigital number, since it uses as much as digits as its factorization.

1053291433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33977174.

The product of its (nonzero) digits is 9720, while the sum is 31.

The square root of 1053291433 is about 32454.4516669131. The cubic root of 1053291433 is about 1017.4572809348.

The spelling of 1053291433 in words is "one billion, fifty-three million, two hundred ninety-one thousand, four hundred thirty-three".