Base | Representation |
---|---|
bin | 10011100111110011… |
… | …00100000101010001 |
3 | 1000012011100012012011 |
4 | 21303321210011101 |
5 | 133033301420213 |
6 | 4501152502521 |
7 | 522023650240 |
oct | 116371440521 |
9 | 30164305164 |
10 | 10534404433 |
11 | 451643aa73 |
12 | 205bb4aa41 |
13 | cbb62a207 |
14 | 71d112957 |
15 | 419c7003d |
hex | 273e64151 |
10534404433 has 8 divisors (see below), whose sum is σ = 12747514752. Its totient is φ = 8498342976.
The previous prime is 10534404427. The next prime is 10534404437. The reversal of 10534404433 is 33440443501.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 10534404433 - 213 = 10534396241 is a prime.
It is a super-2 number, since 2×105344044332 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10534404395 and 10534404404.
It is not an unprimeable number, because it can be changed into a prime (10534404437) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 44262085 + ... + 44262322.
It is an arithmetic number, because the mean of its divisors is an integer number (1593439344).
Almost surely, 210534404433 is an apocalyptic number.
It is an amenable number.
10534404433 is a deficient number, since it is larger than the sum of its proper divisors (2213110319).
10534404433 is an equidigital number, since it uses as much as digits as its factorization.
10534404433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 88524431.
The product of its (nonzero) digits is 34560, while the sum is 31.
Adding to 10534404433 its reverse (33440443501), we get a palindrome (43974847934).
The spelling of 10534404433 in words is "ten billion, five hundred thirty-four million, four hundred four thousand, four hundred thirty-three".
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