1053471180753 has 16 divisors (see below), whose sum is σ = 1583992048960. Its totient is φ = 691831819008.

The previous prime is 1053471180733. The next prime is 1053471180767. The reversal of 1053471180753 is 3570811743501.

1053471180753 is a `hidden beast` number, since 1 + 0 + 53 + 471 + 1 + 80 + 7 + 53 = 666.

It is not a de Polignac number, because 1053471180753 - 2¹⁷ = 1053471049681 is a prime.

It is a super-3 number, since 3×1053471180753³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1053471180699 and 1053471180708.

It is not an unprimeable number, because it can be changed into a prime (1053471180733) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 291173200 + ... + 291176817.

It is an arithmetic number, because the mean of its divisors is an integer number (98999503060).

Almost surely, 2^{1053471180753} is an apocalyptic number.

It is an amenable number.

1053471180753 is a deficient number, since it is larger than the sum of its proper divisors (530520868207).

1053471180753 is an equidigital number, since it uses as much as digits as its factorization.

1053471180753 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 582350093 (or 582350087 counting only the distinct ones).

The product of its (nonzero) digits is 352800, while the sum is 45.

The spelling of 1053471180753 in words is "one trillion, fifty-three billion, four hundred seventy-one million, one hundred eighty thousand, seven hundred fifty-three".