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1053473433 = 3834230817
BaseRepresentation
bin111110110010101…
…011101010011001
32201102021222212120
4332302223222121
54124142122213
6252311331453
735051243055
oct7662535231
92642258776
101053473433
114a0727201
12254980b89
1313a34057c
149dcaac65
1562745423
hex3ecaba99

1053473433 has 8 divisors (see below), whose sum is σ = 1421554848. Its totient is φ = 693853824.

The previous prime is 1053473431. The next prime is 1053473441. The reversal of 1053473433 is 3343743501.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1053473433 - 21 = 1053473431 is a prime.

It is a super-2 number, since 2×10534734332 = 2219612548073610978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1053473394 and 1053473403.

It is not an unprimeable number, because it can be changed into a prime (1053473431) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2115160 + ... + 2115657.

It is an arithmetic number, because the mean of its divisors is an integer number (177694356).

Almost surely, 21053473433 is an apocalyptic number.

It is an amenable number.

1053473433 is a deficient number, since it is larger than the sum of its proper divisors (368081415).

1053473433 is an equidigital number, since it uses as much as digits as its factorization.

1053473433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4230903.

The product of its (nonzero) digits is 45360, while the sum is 33.

The square root of 1053473433 is about 32457.2554754711. The cubic root of 1053473433 is about 1017.5158802786.

The spelling of 1053473433 in words is "one billion, fifty-three million, four hundred seventy-three thousand, four hundred thirty-three".

Divisors: 1 3 83 249 4230817 12692451 351157811 1053473433