1054013441 has 4 divisors (see below), whose sum is σ = 1135091412. Its totient is φ = 972935472.

The previous prime is 1054013419. The next prime is 1054013453. The reversal of 1054013441 is 1443104501.

1054013441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1443104501 = 37277 ⋅38713.

It can be written as a sum of positive squares in 2 ways, for example, as 92083216 + 961930225 = 9596^2 + 31015^2 .

It is a cyclic number.

It is not a de Polignac number, because 1054013441 - 2¹⁸ = 1053751297 is a prime.

It is a super-2 number, since 2×1054013441² = 2221888667617320962, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1054013461) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40538966 + ... + 40538991.

It is an arithmetic number, because the mean of its divisors is an integer number (283772853).

Almost surely, 2^1054013441 is an apocalyptic number.

It is an amenable number.

1054013441 is a deficient number, since it is larger than the sum of its proper divisors (81077971).

1054013441 is an equidigital number, since it uses as much as digits as its factorization.

1054013441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 81077970.

The product of its (nonzero) digits is 960, while the sum is 23.

The square root of 1054013441 is about 32465.5731660478. The cubic root of 1054013441 is about 1017.6897093283.

Adding to 1054013441 its reverse (1443104501), we get a palindrome (2497117942).

The spelling of 1054013441 in words is "one billion, fifty-four million, thirteen thousand, four hundred forty-one".